File	Doc	Category	Size	Date	Package
XNumber.java	API Doc	Java SE 5 API	9844	Fri Aug 26 14:56:10 BST 2005	com.sun.org.apache.xpath.internal.objects

XNumber

• java.lang.Object
  • com.sun.org.apache.xpath.internal.Expression
    • com.sun.org.apache.xpath.internal.objects.XObject

Fields Summary
double	m_val Value of the XNumber object.

Constructors Summary
public XNumber(double d) Construct a XNodeSet object. param d Value of the object super(); m_val = d;
public XNumber(Number num) Construct a XNodeSet object. param d Value of the object super(); m_val = num.doubleValue(); m_obj = num;

Methods Summary
public boolean	bool() Cast result object to a boolean. return false if the value is NaN or equal to 0.0 return (Double.isNaN(m_val) || (m_val == 0.0)) ? false : true;
public void	callVisitors(com.sun.org.apache.xpath.internal.ExpressionOwner owner, com.sun.org.apache.xpath.internal.XPathVisitor visitor) see XPathVisitable#callVisitors(ExpressionOwner, XPathVisitor) visitor.visitNumberLiteral(owner, this);
public boolean	equals(com.sun.org.apache.xpath.internal.objects.XObject obj2) Tell if two objects are functionally equal. param obj2 Object to compare this to return true if the two objects are equal throws javax.xml.transform.TransformerException // In order to handle the 'all' semantics of // nodeset comparisons, we always call the // nodeset function. int t = obj2.getType(); try { if (t == XObject.CLASS_NODESET) return obj2.equals(this); else if(t == XObject.CLASS_BOOLEAN) return obj2.bool() == bool(); else return m_val == obj2.num(); } catch(javax.xml.transform.TransformerException te) { throw new com.sun.org.apache.xml.internal.utils.WrappedRuntimeException(te); }
public int	getType() Tell that this is a CLASS_NUMBER. return node type CLASS_NUMBER return CLASS_NUMBER;
public java.lang.String	getTypeString() Given a request type, return the equivalent string. For diagnostic purposes. return type string "#NUMBER" return "#NUMBER";
public boolean	isStableNumber() Tell if this expression returns a stable number that will not change during iterations within the expression. This is used to determine if a proximity position predicate can indicate that no more searching has to occur. return true if the expression represents a stable number. return true;
public double	num() Cast result object to a number. return the value of the XNumber object return m_val;
public double	num(com.sun.org.apache.xpath.internal.XPathContext xctxt) Evaluate expression to a number. return 0.0 throws javax.xml.transform.TransformerException return m_val;
public java.lang.Object	object() Return a java object that's closest to the representation that should be handed to an extension. return The value of this XNumber as a Double object if(null == m_obj) m_obj = new Double(m_val); return m_obj;
public java.lang.String	str() Cast result object to a string. return "NaN" if the number is NaN, Infinity or -Infinity if the number is infinite or the string value of the number. if (Double.isNaN(m_val)) { return "NaN"; } else if (Double.isInfinite(m_val)) { if (m_val > 0) return "Infinity"; else return "-Infinity"; } double num = m_val; String s = Double.toString(num); int len = s.length(); if (s.charAt(len - 2) == '." && s.charAt(len - 1) == '0") { s = s.substring(0, len - 2); if (s.equals("-0")) return "0"; return s; } int e = s.indexOf('E"); if (e < 0) { if (s.charAt(len - 1) == '0") return s.substring(0, len - 1); else return s; } int exp = Integer.parseInt(s.substring(e + 1)); String sign; if (s.charAt(0) == '-") { sign = "-"; s = s.substring(1); --e; } else sign = ""; int nDigits = e - 2; if (exp >= nDigits) return sign + s.substring(0, 1) + s.substring(2, e) + zeros(exp - nDigits); // Eliminate trailing 0's - bugzilla 14241 while (s.charAt(e-1) == '0") e--; if (exp > 0) return sign + s.substring(0, 1) + s.substring(2, 2 + exp) + "." + s.substring(2 + exp, e); return sign + "0." + zeros(-1 - exp) + s.substring(0, 1) + s.substring(2, e);
private static java.lang.String	zeros(int n) Return a string of '0' of the given length param n Length of the string to be returned return a string of '0' with the given length if (n < 1) return ""; char[] buf = new char[n]; for (int i = 0; i < n; i++) { buf[i] = '0"; } return new String(buf);