Doublepublic final class Double extends Number implements ComparableThe Double class wraps a value of the primitive type
double in an object. An object of type
Double contains a single field whose type is
double .
In addition, this class provides several methods for converting a
double to a String and a
String to a double , as well as other
constants and methods useful when dealing with a
double . |
Fields Summary |
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public static final double | POSITIVE_INFINITYA constant holding the positive infinity of type
double . It is equal to the value returned by
Double.longBitsToDouble(0x7ff0000000000000L) . | public static final double | NEGATIVE_INFINITYA constant holding the negative infinity of type
double . It is equal to the value returned by
Double.longBitsToDouble(0xfff0000000000000L) . | public static final double | NaNA constant holding a Not-a-Number (NaN) value of type
double . It is equivalent to the value returned by
Double.longBitsToDouble(0x7ff8000000000000L) . | public static final double | MAX_VALUEA constant holding the largest positive finite value of type
double ,
(2-2-52)·21023. It is equal to
the hexadecimal floating-point literal
0x1.fffffffffffffP+1023 and also equal to
Double.longBitsToDouble(0x7fefffffffffffffL) . | public static final double | MIN_NORMALA constant holding the smallest positive normal value of type
{@code double}, 2-1022. It is equal to the
hexadecimal floating-point literal {@code 0x1.0p-1022} and also
equal to {@code Double.longBitsToDouble(0x0010000000000000L)}. | public static final double | MIN_VALUEA constant holding the smallest positive nonzero value of type
double , 2-1074. It is equal to the
hexadecimal floating-point literal
0x0.0000000000001P-1022 and also equal to
Double.longBitsToDouble(0x1L) . | public static final int | MAX_EXPONENTMaximum exponent a finite {@code double} variable may have.
It is equal to the value returned by
{@code Math.getExponent(Double.MAX_VALUE)}. | public static final int | MIN_EXPONENTMinimum exponent a normalized {@code double} variable may
have. It is equal to the value returned by
{@code Math.getExponent(Double.MIN_NORMAL)}. | public static final int | SIZEThe number of bits used to represent a double value. | public static final Class | TYPEThe Class instance representing the primitive type
double . | private final double | valueThe value of the Double. | private static final long | serialVersionUIDuse serialVersionUID from JDK 1.0.2 for interoperability |
Constructors Summary |
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public Double(double value)Constructs a newly allocated Double object that
represents the primitive double argument.
this.value = value;
| public Double(String s)Constructs a newly allocated Double object that
represents the floating-point value of type double
represented by the string. The string is converted to a
double value as if by the valueOf method.
// REMIND: this is inefficient
this(valueOf(s).doubleValue());
|
Methods Summary |
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public byte | byteValue()Returns the value of this Double as a byte (by
casting to a byte ).
return (byte)value;
| public static int | compare(double d1, double d2)Compares the two specified double values. The sign
of the integer value returned is the same as that of the
integer that would be returned by the call:
new Double(d1).compareTo(new Double(d2))
if (d1 < d2)
return -1; // Neither val is NaN, thisVal is smaller
if (d1 > d2)
return 1; // Neither val is NaN, thisVal is larger
long thisBits = Double.doubleToLongBits(d1);
long anotherBits = Double.doubleToLongBits(d2);
return (thisBits == anotherBits ? 0 : // Values are equal
(thisBits < anotherBits ? -1 : // (-0.0, 0.0) or (!NaN, NaN)
1)); // (0.0, -0.0) or (NaN, !NaN)
| public int | compareTo(java.lang.Double anotherDouble)Compares two Double objects numerically. There
are two ways in which comparisons performed by this method
differ from those performed by the Java language numerical
comparison operators (<, <=, ==, >= > )
when applied to primitive double values:
-
Double.NaN is considered by this method
to be equal to itself and greater than all other
double values (including
Double.POSITIVE_INFINITY ).
-
0.0d is considered by this method to be greater
than -0.0d .
This ensures that the natural ordering of
Double objects imposed by this method is consistent
with equals.
return Double.compare(value, anotherDouble.value);
| public static long | doubleToLongBits(double value)Returns a representation of the specified floating-point value
according to the IEEE 754 floating-point "double
format" bit layout.
Bit 63 (the bit that is selected by the mask
0x8000000000000000L ) represents the sign of the
floating-point number. Bits
62-52 (the bits that are selected by the mask
0x7ff0000000000000L ) represent the exponent. Bits 51-0
(the bits that are selected by the mask
0x000fffffffffffffL ) represent the significand
(sometimes called the mantissa) of the floating-point number.
If the argument is positive infinity, the result is
0x7ff0000000000000L .
If the argument is negative infinity, the result is
0xfff0000000000000L .
If the argument is NaN, the result is
0x7ff8000000000000L .
In all cases, the result is a long integer that, when
given to the {@link #longBitsToDouble(long)} method, will produce a
floating-point value the same as the argument to
doubleToLongBits (except all NaN values are
collapsed to a single "canonical" NaN value).
long result = doubleToRawLongBits(value);
// Check for NaN based on values of bit fields, maximum
// exponent and nonzero significand.
if ( ((result & DoubleConsts.EXP_BIT_MASK) ==
DoubleConsts.EXP_BIT_MASK) &&
(result & DoubleConsts.SIGNIF_BIT_MASK) != 0L)
result = 0x7ff8000000000000L;
return result;
| public static native long | doubleToRawLongBits(double value)Returns a representation of the specified floating-point value
according to the IEEE 754 floating-point "double
format" bit layout, preserving Not-a-Number (NaN) values.
Bit 63 (the bit that is selected by the mask
0x8000000000000000L ) represents the sign of the
floating-point number. Bits
62-52 (the bits that are selected by the mask
0x7ff0000000000000L ) represent the exponent. Bits 51-0
(the bits that are selected by the mask
0x000fffffffffffffL ) represent the significand
(sometimes called the mantissa) of the floating-point number.
If the argument is positive infinity, the result is
0x7ff0000000000000L .
If the argument is negative infinity, the result is
0xfff0000000000000L .
If the argument is NaN, the result is the long
integer representing the actual NaN value. Unlike the
doubleToLongBits method,
doubleToRawLongBits does not collapse all the bit
patterns encoding a NaN to a single "canonical" NaN
value.
In all cases, the result is a long integer that,
when given to the {@link #longBitsToDouble(long)} method, will
produce a floating-point value the same as the argument to
doubleToRawLongBits .
| public double | doubleValue()Returns the double value of this
Double object.
return (double)value;
| public boolean | equals(java.lang.Object obj)Compares this object against the specified object. The result
is true if and only if the argument is not
null and is a Double object that
represents a double that has the same value as the
double represented by this object. For this
purpose, two double values are considered to be
the same if and only if the method {@link
#doubleToLongBits(double)} returns the identical
long value when applied to each.
Note that in most cases, for two instances of class
Double , d1 and d2 , the
value of d1.equals(d2) is true if and
only if
d1.doubleValue() == d2.doubleValue()
also has the value true . However, there are two
exceptions:
- If
d1 and d2 both represent
Double.NaN , then the equals method
returns true , even though
Double.NaN==Double.NaN has the value
false .
- If
d1 represents +0.0 while
d2 represents -0.0 , or vice versa,
the equal test has the value false ,
even though +0.0==-0.0 has the value true .
This definition allows hash tables to operate properly.
return (obj instanceof Double)
&& (doubleToLongBits(((Double)obj).value) ==
doubleToLongBits(value));
| public float | floatValue()Returns the float value of this
Double object.
return (float)value;
| public int | hashCode()Returns a hash code for this Double object. The
result is the exclusive OR of the two halves of the
long integer bit representation, exactly as
produced by the method {@link #doubleToLongBits(double)}, of
the primitive double value represented by this
Double object. That is, the hash code is the value
of the expression:
(int)(v^(v>>>32))
where v is defined by:
long v = Double.doubleToLongBits(this.doubleValue());
long bits = doubleToLongBits(value);
return (int)(bits ^ (bits >>> 32));
| public int | intValue()Returns the value of this Double as an
int (by casting to type int ).
return (int)value;
| public boolean | isInfinite()Returns true if this Double value is
infinitely large in magnitude, false otherwise.
return isInfinite(value);
| public static boolean | isInfinite(double v)Returns true if the specified number is infinitely
large in magnitude, false otherwise.
return (v == POSITIVE_INFINITY) || (v == NEGATIVE_INFINITY);
| public boolean | isNaN()Returns true if this Double value is
a Not-a-Number (NaN), false otherwise.
return isNaN(value);
| public static boolean | isNaN(double v)Returns true if the specified number is a
Not-a-Number (NaN) value, false otherwise.
return (v != v);
| public static native double | longBitsToDouble(long bits)Returns the double value corresponding to a given
bit representation.
The argument is considered to be a representation of a
floating-point value according to the IEEE 754 floating-point
"double format" bit layout.
If the argument is 0x7ff0000000000000L , the result
is positive infinity.
If the argument is 0xfff0000000000000L , the result
is negative infinity.
If the argument is any value in the range
0x7ff0000000000001L through
0x7fffffffffffffffL or in the range
0xfff0000000000001L through
0xffffffffffffffffL , the result is a NaN. No IEEE
754 floating-point operation provided by Java can distinguish
between two NaN values of the same type with different bit
patterns. Distinct values of NaN are only distinguishable by
use of the Double.doubleToRawLongBits method.
In all other cases, let s, e, and m be three
values that can be computed from the argument:
int s = ((bits >> 63) == 0) ? 1 : -1;
int e = (int)((bits >> 52) & 0x7ffL);
long m = (e == 0) ?
(bits & 0xfffffffffffffL) << 1 :
(bits & 0xfffffffffffffL) | 0x10000000000000L;
Then the floating-point result equals the value of the mathematical
expression s·m·2e-1075.
Note that this method may not be able to return a
double NaN with exactly same bit pattern as the
long argument. IEEE 754 distinguishes between two
kinds of NaNs, quiet NaNs and signaling NaNs. The
differences between the two kinds of NaN are generally not
visible in Java. Arithmetic operations on signaling NaNs turn
them into quiet NaNs with a different, but often similar, bit
pattern. However, on some processors merely copying a
signaling NaN also performs that conversion. In particular,
copying a signaling NaN to return it to the calling method
may perform this conversion. So longBitsToDouble
may not be able to return a double with a
signaling NaN bit pattern. Consequently, for some
long values,
doubleToRawLongBits(longBitsToDouble(start)) may
not equal start . Moreover, which
particular bit patterns represent signaling NaNs is platform
dependent; although all NaN bit patterns, quiet or signaling,
must be in the NaN range identified above.
| public long | longValue()Returns the value of this Double as a
long (by casting to type long ).
return (long)value;
| public static double | parseDouble(java.lang.String s)Returns a new double initialized to the value
represented by the specified String , as performed
by the valueOf method of class
Double .
return FloatingDecimal.readJavaFormatString(s).doubleValue();
| public short | shortValue()Returns the value of this Double as a
short (by casting to a short ).
return (short)value;
| public static java.lang.String | toHexString(double d)Returns a hexadecimal string representation of the
double argument. All characters mentioned below
are ASCII characters.
- If the argument is NaN, the result is the string
"
NaN ".
- Otherwise, the result is a string that represents the sign
and magnitude of the argument. If the sign is negative, the
first character of the result is '
- '
('\u002D' ); if the sign is positive, no sign
character appears in the result. As for the magnitude m:
- If m is infinity, it is represented by the string
"Infinity" ; thus, positive infinity produces the
result "Infinity" and negative infinity produces
the result "-Infinity" .
- If m is zero, it is represented by the string
"0x0.0p0" ; thus, negative zero produces the result
"-0x0.0p0" and positive zero produces the result
"0x0.0p0" .
- If m is a
double value with a
normalized representation, substrings are used to represent the
significand and exponent fields. The significand is
represented by the characters "0x1."
followed by a lowercase hexadecimal representation of the rest
of the significand as a fraction. Trailing zeros in the
hexadecimal representation are removed unless all the digits
are zero, in which case a single zero is used. Next, the
exponent is represented by "p" followed
by a decimal string of the unbiased exponent as if produced by
a call to {@link Integer#toString(int) Integer.toString} on the
exponent value.
- If m is a
double value with a subnormal
representation, the significand is represented by the
characters "0x0." followed by a
hexadecimal representation of the rest of the significand as a
fraction. Trailing zeros in the hexadecimal representation are
removed. Next, the exponent is represented by
"p-1022" . Note that there must be at
least one nonzero digit in a subnormal significand.
Examples
Floating-point Value | Hexadecimal String |
---|
1.0 | 0x1.0p0 |
-1.0 | -0x1.0p0 |
2.0 | 0x1.0p1 |
3.0 | 0x1.8p1 |
0.5 | 0x1.0p-1 |
0.25 | 0x1.0p-2 |
Double.MAX_VALUE |
0x1.fffffffffffffp1023 |
Minimum Normal Value |
0x1.0p-1022 |
Maximum Subnormal Value |
0x0.fffffffffffffp-1022 |
Double.MIN_VALUE |
0x0.0000000000001p-1022 |
/*
* Modeled after the "a" conversion specifier in C99, section
* 7.19.6.1; however, the output of this method is more
* tightly specified.
*/
if (!FpUtils.isFinite(d) )
// For infinity and NaN, use the decimal output.
return Double.toString(d);
else {
// Initialized to maximum size of output.
StringBuffer answer = new StringBuffer(24);
if (FpUtils.rawCopySign(1.0, d) == -1.0) // value is negative,
answer.append("-"); // so append sign info
answer.append("0x");
d = Math.abs(d);
if(d == 0.0) {
answer.append("0.0p0");
}
else {
boolean subnormal = (d < DoubleConsts.MIN_NORMAL);
// Isolate significand bits and OR in a high-order bit
// so that the string representation has a known
// length.
long signifBits = (Double.doubleToLongBits(d)
& DoubleConsts.SIGNIF_BIT_MASK) |
0x1000000000000000L;
// Subnormal values have a 0 implicit bit; normal
// values have a 1 implicit bit.
answer.append(subnormal ? "0." : "1.");
// Isolate the low-order 13 digits of the hex
// representation. If all the digits are zero,
// replace with a single 0; otherwise, remove all
// trailing zeros.
String signif = Long.toHexString(signifBits).substring(3,16);
answer.append(signif.equals("0000000000000") ? // 13 zeros
"0":
signif.replaceFirst("0{1,12}$", ""));
// If the value is subnormal, use the E_min exponent
// value for double; otherwise, extract and report d's
// exponent (the representation of a subnormal uses
// E_min -1).
answer.append("p" + (subnormal ?
DoubleConsts.MIN_EXPONENT:
FpUtils.getExponent(d) ));
}
return answer.toString();
}
| public static java.lang.String | toString(double d)Returns a string representation of the double
argument. All characters mentioned below are ASCII characters.
- If the argument is NaN, the result is the string
"
NaN ".
- Otherwise, the result is a string that represents the sign and
magnitude (absolute value) of the argument. If the sign is negative,
the first character of the result is '
- '
('\u002D' ); if the sign is positive, no sign character
appears in the result. As for the magnitude m:
- If m is infinity, it is represented by the characters
"Infinity" ; thus, positive infinity produces the result
"Infinity" and negative infinity produces the result
"-Infinity" .
- If m is zero, it is represented by the characters
"0.0" ; thus, negative zero produces the result
"-0.0" and positive zero produces the result
"0.0" .
- If m is greater than or equal to 10-3 but less
than 107, then it is represented as the integer part of
m, in decimal form with no leading zeroes, followed by
'
. ' ('\u002E' ), followed by one or
more decimal digits representing the fractional part of m.
- If m is less than 10-3 or greater than or
equal to 107, then it is represented in so-called
"computerized scientific notation." Let n be the unique
integer such that 10n <= m <
10n+1; then let a be the
mathematically exact quotient of m and
10n so that 1 <= a < 10. The
magnitude is then represented as the integer part of a,
as a single decimal digit, followed by '
. '
('\u002E' ), followed by decimal digits
representing the fractional part of a, followed by the
letter 'E ' ('\u0045' ), followed
by a representation of n as a decimal integer, as
produced by the method {@link Integer#toString(int)}.
How many digits must be printed for the fractional part of
m or a? There must be at least one digit to represent
the fractional part, and beyond that as many, but only as many, more
digits as are needed to uniquely distinguish the argument value from
adjacent values of type double . That is, suppose that
x is the exact mathematical value represented by the decimal
representation produced by this method for a finite nonzero argument
d. Then d must be the double value nearest
to x; or if two double values are equally close
to x, then d must be one of them and the least
significant bit of the significand of d must be 0 .
To create localized string representations of a floating-point
value, use subclasses of {@link java.text.NumberFormat}.
return new FloatingDecimal(d).toJavaFormatString();
| public java.lang.String | toString()Returns a string representation of this Double object.
The primitive double value represented by this
object is converted to a string exactly as if by the method
toString of one argument.
return String.valueOf(value);
| public static java.lang.Double | valueOf(java.lang.String s)Returns a Double object holding the
double value represented by the argument string
s .
If s is null , then a
NullPointerException is thrown.
Leading and trailing whitespace characters in s
are ignored. Whitespace is removed as if by the {@link
String#trim} method; that is, both ASCII space and control
characters are removed. The rest of s should
constitute a FloatValue as described by the lexical
syntax rules:
- FloatValue:
- Signopt
NaN
- Signopt
Infinity
- Signopt FloatingPointLiteral
- Signopt HexFloatingPointLiteral
- SignedInteger
- HexFloatingPointLiteral:
- HexSignificand BinaryExponent FloatTypeSuffixopt
- HexSignificand:
- HexNumeral
- HexNumeral
.
0x HexDigitsopt
. HexDigits
0X HexDigitsopt
. HexDigits
- BinaryExponent:
- BinaryExponentIndicator SignedInteger
- BinaryExponentIndicator:
p
P
where Sign, FloatingPointLiteral,
HexNumeral, HexDigits, SignedInteger and
FloatTypeSuffix are as defined in the lexical structure
sections of the of the Java Language
Specification. If s does not have the form of
a FloatValue, then a NumberFormatException
is thrown. Otherwise, s is regarded as
representing an exact decimal value in the usual
"computerized scientific notation" or as an exact
hexadecimal value; this exact numerical value is then
conceptually converted to an "infinitely precise"
binary value that is then rounded to type double
by the usual round-to-nearest rule of IEEE 754 floating-point
arithmetic, which includes preserving the sign of a zero
value. Finally, a Double object representing this
double value is returned.
To interpret localized string representations of a
floating-point value, use subclasses of {@link
java.text.NumberFormat}.
Note that trailing format specifiers, specifiers that
determine the type of a floating-point literal
(1.0f is a float value;
1.0d is a double value), do
not influence the results of this method. In other
words, the numerical value of the input string is converted
directly to the target floating-point type. The two-step
sequence of conversions, string to float followed
by float to double , is not
equivalent to converting a string directly to
double . For example, the float
literal 0.1f is equal to the double
value 0.10000000149011612 ; the float
literal 0.1f represents a different numerical
value than the double literal
0.1 . (The numerical value 0.1 cannot be exactly
represented in a binary floating-point number.)
To avoid calling this method on an invalid string and having
a NumberFormatException be thrown, the regular
expression below can be used to screen the input string:
final String Digits = "(\\p{Digit}+)";
final String HexDigits = "(\\p{XDigit}+)";
// an exponent is 'e' or 'E' followed by an optionally
// signed decimal integer.
final String Exp = "[eE][+-]?"+Digits;
final String fpRegex =
("[\\x00-\\x20]*"+ // Optional leading "whitespace"
"[+-]?(" + // Optional sign character
"NaN|" + // "NaN" string
"Infinity|" + // "Infinity" string
// A decimal floating-point string representing a finite positive
// number without a leading sign has at most five basic pieces:
// Digits . Digits ExponentPart FloatTypeSuffix
//
// Since this method allows integer-only strings as input
// in addition to strings of floating-point literals, the
// two sub-patterns below are simplifications of the grammar
// productions from the Java Language Specification, 2nd
// edition, section 3.10.2.
// Digits ._opt Digits_opt ExponentPart_opt FloatTypeSuffix_opt
"((("+Digits+"(\\.)?("+Digits+"?)("+Exp+")?)|"+
// . Digits ExponentPart_opt FloatTypeSuffix_opt
"(\\.("+Digits+")("+Exp+")?)|"+
// Hexadecimal strings
"((" +
// 0[xX] HexDigits ._opt BinaryExponent FloatTypeSuffix_opt
"(0[xX]" + HexDigits + "(\\.)?)|" +
// 0[xX] HexDigits_opt . HexDigits BinaryExponent FloatTypeSuffix_opt
"(0[xX]" + HexDigits + "?(\\.)" + HexDigits + ")" +
")[pP][+-]?" + Digits + "))" +
"[fFdD]?))" +
"[\\x00-\\x20]*");// Optional trailing "whitespace"
if (Pattern.matches(fpRegex, myString))
Double.valueOf(myString); // Will not throw NumberFormatException
else {
// Perform suitable alternative action
}
return new Double(FloatingDecimal.readJavaFormatString(s).doubleValue());
| public static java.lang.Double | valueOf(double d)Returns a Double instance representing the specified
double value.
If a new Double instance is not required, this method
should generally be used in preference to the constructor
{@link #Double(double)}, as this method is likely to yield
significantly better space and time performance by caching
frequently requested values.
return new Double(d);
|
|