//get the file name from the 'file' parameter
String fileName = (String) request.getParameter("file");
if (fileName == null || fileName.equals(""))
throw new ServletException(
"Invalid or non-existent file parameter in SendXml servlet.");
// add the .doc suffix if it doesn't already exist
if (fileName.indexOf(".xml") == -1)
fileName = fileName + ".xml";
//where are Word files kept?
String xmlDir = getServletContext().getInitParameter("xml-dir");
if (xmlDir == null || xmlDir.equals(""))
throw new ServletException(
"Invalid or non-existent xmlDir context-param.");
ServletOutputStream stream = null;
BufferedInputStream buf = null;
try{
stream = response.getOutputStream();
File xml = new File(xmlDir + "/" + fileName);
//set response headers
response.setContentType("text/xml");
response.addHeader(
"Content-Disposition","attachment; filename="+fileName );
response.setContentLength( (int) xml.length() );
FileInputStream input = new FileInputStream(xml);
buf = new BufferedInputStream(input);
int readBytes = 0;
//read from the file; write to the ServletOutputStream
while((readBytes = buf.read()) != -1)
stream.write(readBytes);
} catch (IOException ioe){
throw new ServletException(ioe.getMessage());
} finally {
//close the input/output streams
if(stream != null)
stream.close();
if(buf != null)
buf.close();
}
