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QSortAlgorithm.javaAPI DocSun JDK 1.5.0 Example4683Sat Jan 08 15:09:03 GMT 2005None

QSortAlgorithm.java

/*
 * @(#)QSortAlgorithm.java	1.11 04/07/26
 * 
 * Copyright (c) 2004 Sun Microsystems, Inc. All Rights Reserved.
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 * modification, are permitted provided that the following conditions are met:
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 *  list of conditions and the following disclaimer.
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 * be used to endorse or promote products derived from this software without 
 * specific prior written permission.
 * 
 * This software is provided "AS IS," without a warranty of any kind. ALL 
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 * ANY IMPLIED WARRANTY OF MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE
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 * You acknowledge that this software is not designed, licensed or intended
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/*
 * @(#)QSortAlgorithm.java	1.11 04/07/26
 */

/**
 * A quick sort demonstration algorithm
 * SortAlgorithm.java
 *
 * @author James Gosling
 * @author Kevin A. Smith
 * @version 	@(#)QSortAlgorithm.java	1.3, 29 Feb 1996
 */
public class QSortAlgorithm extends SortAlgorithm
{

    /**
     * A version of pause() that makes it easier to ensure that we pause
     * exactly the right number of times.
     */
    private boolean pauseTrue(int lo, int hi) throws Exception {
	super.pause(lo, hi);
	return true;
    }

   /** This is a generic version of C.A.R Hoare's Quick Sort
    * algorithm.  This will handle arrays that are already
    * sorted, and arrays with duplicate keys.<BR>
    *
    * If you think of a one dimensional array as going from
    * the lowest index on the left to the highest index on the right
    * then the parameters to this function are lowest index or
    * left and highest index or right.  The first time you call
    * this function it will be with the parameters 0, a.length - 1.
    *
    * @param a       an integer array
    * @param lo0     left boundary of array partition
    * @param hi0     right boundary of array partition
    */
   void QuickSort(int a[], int lo0, int hi0) throws Exception
   {
      int lo = lo0;
      int hi = hi0;
      int mid;

      if ( hi0 > lo0)
      {

         /* Arbitrarily establishing partition element as the midpoint of
          * the array.
          */
         mid = a[ ( lo0 + hi0 ) / 2 ];

         // loop through the array until indices cross
         while( lo <= hi )
         {
            /* find the first element that is greater than or equal to
             * the partition element starting from the left Index.
             */
	     while( ( lo < hi0 ) && pauseTrue(lo0, hi0) && ( a[lo] < mid ))
		 ++lo;

            /* find an element that is smaller than or equal to
             * the partition element starting from the right Index.
             */
	     while( ( hi > lo0 ) && pauseTrue(lo0, hi0) && ( a[hi] > mid ))
		 --hi;

            // if the indexes have not crossed, swap
            if( lo <= hi )
            {
               swap(a, lo, hi);
               ++lo;
               --hi;
            }
         }

         /* If the right index has not reached the left side of array
          * must now sort the left partition.
          */
         if( lo0 < hi )
            QuickSort( a, lo0, hi );

         /* If the left index has not reached the right side of array
          * must now sort the right partition.
          */
         if( lo < hi0 )
            QuickSort( a, lo, hi0 );

      }
   }

   private void swap(int a[], int i, int j)
   {
      int T;
      T = a[i];
      a[i] = a[j];
      a[j] = T;

   }

   public void sort(int a[]) throws Exception
   {
      QuickSort(a, 0, a.length - 1);
   }
}